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Solution:
ReplyDeleteL1= language of words having triple a’s.
The regular expression L1 is as below
R.E = (a+b)* (aaa) (a+b)*
L2= language of words containing ab.
The regular expression L2 is as below
RE = (a+b)* (ab) (a+b)*
Using De-Morgan’s law for sets
(L1C U L2C)C = (L1C)C ∩ (L2C)C = L1 ∩ L2
Please check RE of L1 and L2 is correct.
yeh just itna solution h kya is k FAs nhiu hn kya???
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